Rezolvare BAC Informatica 2009 – Varianta 26 – Subiectul al II-lea problema 5
Mai jos puteti gasi rezolvarea problemei 5 de la subiectul II din varianta 26 pentru examenul de bacalaureat din anul 2009
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| #include <iostream.h> | |
| void main() { | |
| int n, i, j, max, gasit = 0; | |
| long p; | |
| int a[10][10]; | |
| cin >> n; | |
| for (i = 1; i <= n; i++) | |
| for (j = 1; j <= n; j++) | |
| cin >> a[i][j]; | |
| for (j = 1; j <= n; j++) { | |
| p = 1; | |
| max = 0; | |
| for (i = 1; i <= n; i++) { | |
| p = p * a[i][j]; | |
| if (a[i][j] > max) | |
| max = a[i][j]; | |
| } | |
| if (p / max == max) { | |
| cout << max << " "; | |
| gasit = 1; | |
| } | |
| } | |
| if (!gasit) | |
| cout << "nu exista"; | |
| } |
by Spor la lucru! Daca aveti intrebari nu ezitati sa le lasati in comentarii, va vom raspunde cat de repede putem 