Rezolvare BAC Informatica 2009 – Varianta 79 – Subiectul al III-lea problema 3
Mai jos puteti gasi rezolvarea problemei 3 de la subiectul III din varianta 79 pentru examenul de bacalaureat din anul 2009
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| #include <iostream> | |
| using namespace std; | |
| void max(float a, float b, float &c) { | |
| float a2 = (int)(a * 1000) % 1000 / 10 + (int)a / 100.0; | |
| float b2 = (int)(b * 1000) % 1000 / 10 + (int)b / 100.0; | |
| c = a; | |
| if (a2 > c) | |
| c = a2; | |
| if (b > c) | |
| c = b; | |
| if (b2 > c) | |
| c = b2; | |
| } | |
| int main() { | |
| float a,b,c; | |
| cin>>a>>b; | |
| max(a,b,c); | |
| cout<<c; | |
| return 0; | |
| } |
by Spor la lucru! Daca aveti intrebari nu ezitati sa le lasati in comentarii, va vom raspunde cat de repede putem 