Rezolvare BAC Informatica 2009 – Varianta 92 – Subiectul al II-lea problema 5
Mai jos puteti gasi rezolvarea problemei 5 de la subiectul II din varianta 92 pentru examenul de bacalaureat din anul 2009
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| #include <iostream> | |
| using namespace std; | |
| int main() { | |
| int m,n,a[24][24],i,j; | |
| cin>>m>>n; | |
| for (i = 0; i < m; i++) | |
| for (j = 0; j < n; j++) | |
| cin>>a[i][j]; | |
| int minim = a[0][0],linie = 0,coloana = 0; | |
| for (i = 0; i < m; i++) | |
| for (j = 0; j < n; j++) | |
| if (a[i][j] < minim){ | |
| minim = a[i][j]; | |
| linie = i; | |
| coloana = j; | |
| } | |
| for (i = 0; i < m; i++) | |
| for (j = coloana; j < n - 1; j++) | |
| a[i][j] = a[i][j + 1]; | |
| n = n - 1; | |
| for (j = 0; j < n; j++) | |
| for (i = linie; i < m - 1; i++) | |
| a[i][j] = a[i + 1][j]; | |
| m = m - 1; | |
| for (i = 0; i < m; i++) { | |
| for (j = 0; j < n; j++) | |
| cout<<a[i][j]<<" "; | |
| cout<<'\n'; | |
| } | |
| return 0; | |
| } |
by Spor la lucru! Daca aveti intrebari nu ezitati sa le lasati in comentarii, va vom raspunde cat de repede putem 