Rezolvare BAC Informatica 2009 – Varianta 92 – Subiectul al III-lea problema 3
Mai jos puteti gasi rezolvarea problemei 3 de la subiectul III din varianta 92 pentru examenul de bacalaureat din anul 2009
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| #include <iostream> | |
| using namespace std; | |
| void ordonare(float *x, int n) { | |
| int sortat,i; | |
| do { | |
| sortat = 1; | |
| for (i = 0; i < n - 1; i++) | |
| if (x[i] > x[i + 1]) { | |
| float aux = x[i]; | |
| x[i] = x[i + 1]; | |
| x[i + 1] = aux; | |
| sortat = 0; | |
| } | |
| }while (sortat == 0); | |
| } | |
| int main() { | |
| float x[100]; | |
| int n,m,i; | |
| cin>>n>>m; | |
| for (i = 0; i < n; i++) | |
| cin>>x[i]; | |
| ordonare(x,n); | |
| for (i = n - m; i <= n - 1; i++) | |
| cout<<x[i]<<" "; | |
| cout<<'\n'; | |
| for (i = m - 1; i >= 0; i--) | |
| cout<<x[i]<<" "; | |
| return 0; | |
| } |
by Spor la lucru! Daca aveti intrebari nu ezitati sa le lasati in comentarii, va vom raspunde cat de repede putem 