Rezolvare BAC Informatica 2009 – Varianta 96 – Subiectul al III-lea problema 3
Mai jos puteti gasi rezolvarea problemei 3 de la subiectul III din varianta 96 pentru examenul de bacalaureat din anul 2009
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| #include <iostream> | |
| using namespace std; | |
| int verif(int a, int b, int c) { | |
| if (a * b * c == 0) | |
| return 0; | |
| if (c > a + b) | |
| return 0; | |
| if (b > a + c) | |
| return 0; | |
| if (a > b + c) | |
| return 0; | |
| return 1; | |
| } | |
| void ordonare(int &a, int &b, int &c) { | |
| int aux; | |
| if (a > c) { | |
| aux = a; | |
| a = c; | |
| c = aux; | |
| } | |
| if (a > b) { | |
| aux = a; | |
| a = b; | |
| b = aux; | |
| } else if (b > c) { | |
| aux = b; | |
| b = c; | |
| c = aux; | |
| } | |
| } | |
| int main() { | |
| int a1,b1,c1,a2,b2,c2; | |
| cin>>a1>>b1>>c1>>a2>>b2>>c2; | |
| if (verif(a1,b1,c1) && verif(a2,b2,c2)) { | |
| int aux; | |
| ordonare(a1,b1,c1); | |
| ordonare(a2,b2,c2); | |
| if (a1 != a2 || b1 != b2 || c1 != c2) | |
| cout<<"necongruente"; | |
| else | |
| cout<<"congruente"; | |
| } else | |
| cout<<"nu"; | |
| return 0; | |
| } |
by Spor la lucru! Daca aveti intrebari nu ezitati sa le lasati in comentarii, va vom raspunde cat de repede putem 